NCERT Solutions class 7 Maths Chapter-10 Exercise 10.2

NCERT Solutions Class-7 Maths chapter-10 line and angle Exercise-10.2 is prepared by academic team of pw all the questions of NCERT text book are solved step by step with proper and detail solutions explaining each and every questions . For More and additional questions of CBSE class 7 maths you can go to class 7 maths sections. NCERT class 7 Maths Solutions is the best way to enhanced your mathematics skill. And pw practice worksheet & question bank will help you a lot . 

NCERT Solutions class 7 Maths Chapter-10 line and angle

line and angle properties Exercise-10.2

Solutions of Chapter line and angle Exercise-10.2

Question 1:
Construct XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
Answer:
The rough figure of this triangle is as follows.

The required triangle is constructed as follows.
(i) Draw a line segment YZ of length 5 cm.

(ii) Point X is at a distance of 4.5 cm from point Y. Therefore, taking point Y as centre, draw an arc of 4.5 cm radius.

(iii) Point X is at a distance of 6 cm from point Z. Therefore, taking point Z as centre, draw an arc of 6 cm radius. Mark the point of intersection of the arcs as X. Join XY and XZ.

XYZ is the required triangle.

Question 2:
Construct an equilateral triangle of side 5.5 cm.
Answer:
An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. The steps of construction are as follows.
(i) Draw a line segment BC of length 5.5 cm.

(ii) Taking point B as centre, draw an arc of 5.5 cm radius.

(iii) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.

(iv) Join A to B and C.

ABC is the required equilateral triangle.

Question 3:
Draw PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?
Answer:
The steps of construction are as follows.
(i) Draw a line segment QR of length 3.5 cm.

(ii) Taking point Q as centre, draw an arc of 4 cm radius.

(iii) Taking point R as centre, draw an arc of 4 cm radius to intersect the previous arc at point P.

(iv) Join P to Q and R.

PQR is the required triangle. As the two sides of this triangle are of the same length (PQ = PR), therefore, ?PQR is an isosceles triangle.

Question 4:
Construct ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.
Answer:
The steps of construction are as follows.
(i) Draw a line segment BC of length 6 cm.

(ii) Taking point C as centre, draw an arc of 6.5 cm radius.

(iii) Taking point B as centre, draw an arc of radius 2.5 cm to meet the previous arc at point A.

(iv) Join A to B and C.

ABC is the required triangle. ∠B can be measured with the help of protractor. It comes to 90º.

NCERT CLASS 7 MATHEMATICS SOLUTIONS