NCERT Solutions class 7 Maths Chapter-6 Exercise 6.1
NCERT Solutions Class-7 Maths chapter-6 Triangle and its properties Exercise-6.1 is prepared by academic team of pw all the questions of NCERT text book are solved step by step with proper and detail solutions explaining each and every questions . For More and additional questions of CBSE class 7 maths you can go to class 7 maths sections. NCERT class 7 Maths Solutions is the best way to enhanced your mathematics skill. And pw practice worksheet & question bank will help you a lot .
NCERT Solutions class 7 Maths Chapter-6 Triangle and its properties
Triangle and its properties Exercise-6.1
Solutions of Chapter Triangle and its properties Exercise-6.1
Question 1:
In ∆PQR ,D is the mid-point of .
is __________.
PD is ___________.
Is QM = MR?
Answer:
In the above given question, we have
∆PQR
Also, given that:
D is the mid-point of
Therefore,
is altitude
Also,
is Median
And,
QM ≠ MR
Question 2:
Draw rough sketches for the following:
(a) In ∆ABC, BE is a median.
(b) In ∆PQR ,PQ and PR are altitudes of the triangle.
(c) In ∆XYZ, YL is an altitude in the exterior of the triangle.
Answer:
(a) In ∆ABC, BE is a median.
We have,
∆ABC,
And in this triangle BE is a median
Therefore,
The rough sketch for the given figure is as follows:
(b) In ∆PQR ,PQ and PR are altitudes of the triangle.
We have,
∆PQR,
And in this triangle PQ and QR are the altitudes of the triangle
Therefore,
The rough sketch for the given figure is as follows:
(c) In ∆XYZ, YL is an altitude in the exterior of the triangle.
We have,
∆XYZ,
And in this triangle YL is an altitude in the exterior of the triangle
Therefore,
The rough sketch for the given figure is as follows:
Question 3:
Verify by drawing a diagram, if the median and altitude of an isosceles triangle can be same.
Answer:
We have to prove that:
The median and altitude of an isosceles triangle are same
The diagram for the given question is as follows:
This can be proved as follows:
First of all we have to draw a line segment AD which is perpendicular to BC. This is an altitude for this triangle
Now,
From the figure it can also be observed that the length of BD and DC is also same
Therefore,
AD is also median of this isosceles triangle
Hence, proved
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