. (a) Calculate the mass of ammonia that can be obtained from 21.4 g of NH4Cl by the reaction


(a) Calculate the mass of ammonia that can be obtained from 21.4 g of NH4Cl by the reaction:

2NH4Cl + Ca(OH)2CaCl2 +2H2O + 2NH3

(b) What will be the volume of ammonia when measured at S.T.P?

The molar volume of a gas = 22.4 litres at STP.

 

Best Answer

2NH4Cl + Ca(OH)2→CaCl2+2H2O + 2NH3

2 V1 V1 V2 V

Mol. Mass of 2NH4Cl = 2[14 + (1 ×4) + 35.5] = 2[53.5] = 107 g

(a) 107 g NH4Cl gives = 34 g NH3

So, 21.4 g NH4Cl will give = 21.4×34/107 = 6.8 g NH3

(b) The volume of 17 g NH3 is 22.4 litre

So, volume of 6.8 g will be = 6.8×22.4/17 = 8.96 litre

Talk to Our counsellor