. (a) The mass of 5.6 litres of a certain gas at S.T.P. is 12 g

(a) The mass of 5.6 litres of a certain gas at S.T.P. is 12 g. What is the relative molecular mass or molar mass of the gas?

(b) Calculate the volume occupied at S.T.P. by 2 moles of SO₂.

(a) 5.6 litres of gas at STP has mass = 12 g

So, 22.4 litre (molar volume) has mass =12 x 22.4/5.6

= 48g(molar mass)

(b)1 mole of SO₂ has volume = 22.4 litres

So, 2 moles will have = 22.4 x 2 = 44.8 litre

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