. 1/2 N2 + 3/2 H2 ⇌ NH3
1/2 N2 + 3/2 H2 ⇌ NH3
ΔGof for NH3 Is – 16.6 kJ/mol. if we that this reaction occues with ideal gases at standard conditions (T =298o K), what is the equilibrium constant Keq?
A. Keq = exp (16.6 × 103 / R.298)
B. Keq = exp (-16.6 / R.298)
C. Keq = exp (R.298 / 16.6)
D. Keq = exp (-16.6 / R.298)
Best Answer
Correct Answer is:
A. Keq = exp (16.6 × 103 / R.298)
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