. 10 g of ice at 0oC absorbs 5460 J of heat energy to melt and change to
10 g of ice at 0oC absorbs 5460 J of heat energy to melt and change to water at 50oC. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg-1 K-1.
Best Answer
Mass of ice = 10 g
= 0.01 kg
Amount of heat energy absorbed, Q = 5460 J
Specific latent heat of fusion of ice =?
Specific heat capacity of water = 4200 J kg-1 K-1
Amount of heat energy required by 10 g (0.01 kg) of water at 00 C to raise its temperature by 500 C = 0.01 × 4200 × 50
= 2100 J
Let Specific latent heat of fusion of ice = L Jg-1
Then,
Q = mL + mc△t
5460 J = 10 × L + 2100 J
L = 3360 / 10
L = 336 J g-1
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