. A and B throw alternatively a pair of dice


A wins if he throws a sum of 6 before B throws a sum of 7 and B wins if he throws sum of 7 before A throws a sum of 6. Find their respective chance of winning, If A begins.

 

 

Best Answer

Explanation

The total outcome for throwing a pair of dice is 36.

And the favourable outcome that A throws a sum of 6 is 5{ (1,5), (5,1), (2,4), (4,2), (3,3) }  So the probability of A will be 536.

the favourable outcome that A throws a sum of 7 is 6{(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)}

So the probability of B will be 636.

Therefore the probability that A wins is536+313656536+313656313656536

=5361-313656

=3061

Final Answer

The probability that A wins is 3061.

 

 

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