. A ball is gently dropped from a height of 20 m.

If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground? After what time will it strike the ground

Best Answer

Answer: Given, initial velocity of the ball (u) = 0 (since it began at the rest position)

Distance traveled by the ball (s) = 20m

Acceleration (a) = 10 ms-2

As per the third motion equation,


= 2*(10ms-2)*(20m) + 0

v2 = 400m2s-2

Therefore, v= 20ms-1

The ball hits the ground with a velocity of 20 meters per second.

As per the first motion equation,

Therefore, t = (v-u)/a

= (20-0)ms-1 / 10ms-2

= 2 seconds

Therefore, the ball reaches the ground after 2 seconds.

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