. A battery is used to charge a parallel plate capacitor till the potential difference

between the plates becomes equal to the electromotive force of the battery.

The ratio of the energy stored in the capacitor and the work done by the battery will be :

A: 1/2

B: 1

C: 2

D: ¼

Best Answer

Explanation

Let be the emf of the battery
Then the charge gained by the battery q =CE
Now, the work done by the battery:

W =qE

W =( CE) E

W =CE²

Now, the energy stored in the capacitor U =1/2CE²
As a result, the energy stored in the capacitor to the work done by the battery is,

1/2CE²

CE²

⁼1/2

Final Answer

The correct answer is 1/2 i.e A.

Related questions

Related Links