. A battery of emf 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm in series. Find

A battery of emf 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm in series. Find:

(a) the current through the battery

(b) the p.d. between the terminals of the battery.

(a) ε = 15 V

R = 6 + 3

R = 9 ohm

r = 3 ohm

I =?

I = ε / (R + r)

I = 15 / (9 + 3)

I = 15 / 12

I = 1.25 A

(b) Current I = 1.25 A [calculated in part (a)]

External resistance R = 6 + 3

R = 9 ohm

V = IR

V = 1.25 × 9

V = 11.25 V

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