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  3. A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation

. A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation

2x-y=2 . Then the equation of the circle 

was

Best Answer

Answer: The line joining (4, 3) and (2, 1) is also along a diameter. So, the centre is the intersection of the diameters were

Solving these, the centre = (1, 0)

were

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