. A rectangular hyperbola, with centre C, is intersected by a circle of radius r in four points P, Q, R and S

Prove that was


Best Answer

Answer: Let the equation of the circle be x2 + y2 = r2. The rectangular hyperbola intersects the circle in four points. Let (h, k) be the centre of the hyperbola and let (rcosqi, rsinqi) i = 1, 2, 3, 4 be the four points of intersection namely P, Q, R and S. Hence by using the fact that mean point of the points of intersection of circle and rectangular hyperbola is mid point of the line segment joining the centre of circle and that of rectangular hyperbola, we have 



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