. A solution containing
10 g per dm3 of urea (molecular mass = 60 g mol-1) is isotonic with a 5% solution of a non volatile solute.
The molecular mass of this non volatile solute is
(a) 300 g mol-1
(b) 350 g mol-1
(c) 200 g mol-1
(d) 250 g mol-1
Best Answer
Solution ||| Suppose the molecular mass of non volatile solute is M
Molar conc. Of urea solution = 10/60 per dm3
Molar conc. Of non volatile solute solution
= 5/M per 100 mL
= 50/M per dm3
For isotonic solution at the same temperature molar concentration are equal
10/60 = 50/M
M = 300g mol-1
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