. A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the


A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The lime PQ cuts the surface at the point O, and PO = OQ. The distance PO is equal to:

 

  • (A):5R
  • (B):3 R
  • (C):2 R
  • (D):1.5 R

Best Answer

Correct Answer:

(A): 5R

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