# . A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD

A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively (see Fig. 10.14). Find the sides AB and AC.

Solution:

Let the given circle touch the sides AB and AC of the triangle at point E and F respectively and the length of the line segment AF be x.

In ∆ABC,

CF = CD = 6cm (Tangents on the circle from point C)

BE = BD = 8cm (Tangents on the circle from point B)

AE = AF = x (Tangents on the circle from point A)

AB = AE + EB = x + 8

BC = BD + DC = 8 + 6 = 14

CA = CF + FA = 6 + x

2S = AB + BC + CA

= x + 8 + 14 + 6 + x

= 28 + 2x

= 42x+3x2 = 196+x2+28x

= 2x2+14x-196 = 0

= x2 +7x-98 = 0

= x2 14x-7x-98 =0

= x(x+14)-7(x+14) = 0

=(x+14)(x-7) = 0

Either x+14 = 0 or x - 7 =0

Therefore, x = - 14 and 7

However, x = - 14 is not possible as the length of the sides will be negative.

Therefore, x = 7

Hence, AB = x + 8 = 7 + 8 = 15 cm

CA = 6 + x = 6 + 7 = 13 cm