. An aeroplane leaves an airport and flies due north


at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies

due west at a speed of 1200 km per hour. How far apart will be the two planes after 1 12 hours?

 

Best Answer

Explanation:

It is given that the speed of first aeroplane is 1000km/h and speed of second aeroplane is 1200km/h.

The diagrammatic representation of the condition is

aeroplane leaves

Distance covered by plane flying due North is

Distance =speed×time

=1000×1 1/2=1000×3/2=1500km

Distance covered by plane flying due west is

Distance =speed×time

=1200×1 1/2=1200×3/2=1800km

We get the value of OB,OA.

The value of needs to be calculated which is the distance between the planes. This can be done by Pythagoras theorem.

AB2=AO2+OB2

AB2=15002+18002

AB2=2250000+3240000

AB=√5490000=300√61km

Final Answer:

The two planes after 1 1/2 hours will be 300√61km.

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