. An electric bulb is marked 100 W 230 V

If the supply voltage drops to 115 V, what will be the total heat and light energy, total liberated by the bulb in 20 minutes?

Explanation:

The bulb is rated 100W,220W

The maximum current drawn

I=P/4

=100/220=5/11A

When the voltage is 115V,then the power consumed given by,

P=VI

=115X(5/11)=52.28J/s

But it is lighted for 20 minutes,so the total energy consumed by

E=PXT=52.28X20X60=62736J

Final Answer:

Hence,62736J will be liberated by the bulb in 20 minutes from of heat and light energy

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