. An object is dropped from rest at a height of 150 m and simultaneously another
An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time
Best Answer
Initial difference in height = (150 – 100) m = 50 m
Distance travelled by first body in 2 s = h1
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Distance travelled by another body in
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After 2 s, height at which the first body will be = h ′ = 150 – 2 g
After 2 s, height at which the second body will be = h2
Thus, after 2 s, difference in height = 150 – 2 g – (100 – 2 g)
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