. An object is dropped from rest at a height of 150 m and simultaneously another


An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time

Best Answer

Initial difference in height  = (150 – 100) m = 50 m 

 

Distance travelled by first body in 2 s = h1

 

An object is dropped from rest at a height of 150 m and simultaneously another

 

Distance travelled by another body in

 

An object is dropped from rest at a height of 150 m and simultaneously another

 

 

After 2 s, height  at which the first body will  be = h ′    = 150 – 2 g

 

After 2 s, height at which the second body will  be = h2

 

An object is dropped from rest at a height of 150 m and simultaneously another

 

 

 

 

Thus, after 2 s, difference in height = 150 – 2 g – (100 – 2 g)

 

 

 

Talk to Our counsellor