. An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms–1 to 8 ms–1 in 6 s

Best Answer

Answer: Given, mass of the object (m) = 100kg

Initial velocity (u) = 5 m/s

Terminal velocity (v) = 8 m/s

Time period (t) = 6s

Now, initial momentum (m × u) = 100kg × 5m/s = 500 kg.m.s-1

Final momentum (m × v) = 100kg × 8m/s = 800 kg.m.s-1

Therefore, the object accelerates at 0.5 ms-2. This implies that the force acting on the object (F = ma) is equal to:

F = (100kg) × (0.5 ms-2) = 50 N

Therefore, a force of 50 N is applied on the 100kg object, which accelerates it by 0.5 ms-2.