. Boron has two isotopes

B - 10 and B - 11 , the average atomic mass of boron is found to be 10.80 u . Calculate the percentage of abundance of these isotopes.

Explanation:

We have been given the average mass of boron i.e. 10.80 u.

Now, we will let the abundance of B-10 be x% and that of B-11 be (100-x)%.

Now, we will calculate the average mass of boron,

Average mass of boron=x×10+(100-x)×11

10.80=10+1100-11x/100

1080=1100-x

x=20

So, the percentage abundance of B-10 is 20% and that of B-11 is 80%.

Final answer:

Hence, the percentage abundance of B-10 is 20% and that of B-11 is 80%.

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