. Calculate the Molarity of pure water using the density to be 1000 kg m−3
The number of moles of solute which is present in 1 litre volume of solution. It is represented by M.
Formula of Molarity: Moles of the solute/Volume of the solution
Given, density of pure water is 1000 kg m−3
We know 1 kg of water contains 1000 g of water.
1 kg = 1000 g
And we know that a 1-meter cube is equal to 1000 litre.
1 m3= 1000L
So, we can express the density of water in g L−1.
So, the1000 kg m−3 is equal to:
1000/1000 x 1000= 1000 gL−1
So, the density is 1000gL−1
Molarity=Moles of the solute/Volume of the solution=55.55/1=55.55 M
Hence, Molarity of pure water is 55.55 M.