. Calculate the Molarity of pure water using the density to be 1000 kg m−3

Best Answer

The number of moles of solute which is present in 1 litre volume of solution. It is represented by M.

Formula of Molarity: Moles of the solute/Volume of the solution

Given, density of pure water is 1000 kg m⁻³

We know 1 kg of water contains 1000 g of water.

1 kg = 1000 g

And we know that a 1-meter cube is equal to 1000 litre.

1 m³= 1000L

So, we can express the density of water in g L⁻¹.

So, the1000 kg m⁻³ is equal to:

1000/1000 x 1000= 1000 gL⁻¹

So, the density is 1000gL⁻¹

Molarity=Moles of the solute/Volume of the solution=55.55/1=55.55 M

Hence, Molarity of pure water is 55.55 M.