. Calculate the number of atoms of each kind in 5.3 grams of sodium carbonate.
Best Answer
Molecular mass of Na2CO3 = 106 g
106 g has 2 x 6.023 x1023 atoms of Na
So, 5.3g will have = 2 x 6.023 x1023x 5.3/106=6.022 x1022 atoms
Number of atoms of C = 6.023 x1023 x 5.3/106 = 3.01 x 1022 atoms
And atoms of O = 3 x 6.023 x 1023 x 5.3/106= 9.03 x1022 atoms
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