. Combustion of glucose takes place according to the equation
C6H12O6 + 6O2→ 6CO2 + 6H2O, ∆H = −72 k-cal
The energy required for combustion of 1.6 g of glucose is
A. 0.064 k-cal
B. 0.64 k-cal
C. 6.4 k-cal
D. 64 k-cal
Best Answer
(b)
Related questions
