. Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml
The molality of the solution is
A: 1.14 mol kg^-1
B: 3.28 mol kg^-1
C: 2.28 mol kg^-1
D: 0.44 mol kg^-1
Best Answer
Explanation :
•Mass of 1 L solution of 2.05 M acetic acid =1.02g/ml x1000ml=1020 g
•Mass of solute in solution
=2.05 mol/Lx60g/mol=123g/ L,
where molar mass of acetic acid 60g/ mol.
•Mass of solvent in 1 L solution=1020-123=897g
•Molality of the solutions
=(2.05x1000)/(897)= 2.28 mol kg^-1
Correct Option is: (C) 2.28 mol kg^-1
Related questions
