. Discuss the Problem-Solving Strategy in Horizontal Phasor
i. Let us assume a circle of radius equal to the amplitude of SHM.
ii. Assume a particle rotating in a circular path moving with constant same as that of simple harmonic motion in the clockwise direction.
iii. Angle made by the particle at t = 0 with the upper vertical axis is equal to φ (phase constant).
iv. The horizontal component of the velocity of a particle gives you the velocity of a particle performing the simple harmonic motion.
v. The component of the acceleration of a particle in the horizontal direction is equal to the acceleration of the particle performing SHM. [In uniform circular acceleration centripetal only ac = ω2A].