. Draw a triangle ABC with side BC = 6 cm, AB = 5 cm
and ∠ ABC = 60°. Then construct a triangle whose sides are 3/4of the corresponding sides of the triangle ABC.
Solution: Steps of construction:
i. Now in order to make a triangle, draw a line segment AB = 5 cm.
ii. Construct a 60o angle from point B and then draw BC = 6 cm.
iii. Join A C to get the triangle ABC.
iv. Now, dividing the base, draw a ray at an acute angle from BA.s
v. Plot 4 points on BA so that BB1 = B1B2 = B2B3 = B33B4.
vi. Join B4 to point A.
vii. Draw a line from B3such that it is parallel to B4A so that it meets AB at point A’.
viii. Draw A’C’ || AC.
Triangle A’C’B is the required triangle.