- Question Answer
- Explain the case of Impulsive tension when Both ends of the string attached to movable objects
. Explain the case of Impulsive tension when Both ends of the string attached to movable objects
In this case equal and opposite impulses act on the two objects, producing equal and opposite changes in momentum. The total momentum of the system therefore remains constant, although the momentum of each individual object is changed in the direction of the string. Perpendicular to the string no impulse acts and hence momentum of each object in this direction remains unchanged.
Let there be two particles A and B of masses m1 and m2 are respectively attached to the two ends of a light string. Let J be an external impulse imparted to one of the particles (A say), as shown in figure. The component of impulse along and normal to the string will be J cos and J sin respectively. If v be the velocity of the two particles along the string and J' be the impulse communicated along the string then, for particle A.