. Father is aged three times more than his son Ronit
After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A: 2 times
B: 2 1/2 times
C: 2 1/2times
D: 3 times
Let the age of Rohit be x
Then his father’s age will be 3x + x=4x
After 8 years, Rohit’s age -x+8
And father’s age =5/2(x+8)
So we have,
After 8 years Rohit’s age is 16 years.
And father’s age will be 8×4+8=40
So after 8 more years, Rohit’s age is 16+8=24 years.
And father’s age will be 40+8=48 years
So the ratio of age =48/24=2
Option A is the correct choice.i.e 2 times