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- Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive
. Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive
Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide
Best Answer
There is one octahedral hole for each atom in hexagonal close packed arrangement. If the number of oxide ions (O2-) per unit cell is 1, then the number of Fe3+ ions = 2/3 × octahedral holes = 2/3 × 1 = 2/3. Thus, the formula of the compound = Fe2/3 O1 or Fe2O3.
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