. Find the area of the triangle whose vertices are
i. (2, 3), (–1, 0), (2, – 4)
ii. (–5, –1), (3, –5), (5, 2)
Best Answer
Solution: Area of the triangle = [x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)
i. Area of the triangle = [2 (0+ 4) - 1 (-4 – 3) + 2 (3 – 0)
= 1/2(8+7+6)
= 21/2 Square units
ii. Area of the triangle = [-5 (-5 – 2) + 3 (2+ 1) + 5 (-1+ 5)
= 1/2 (35 + 9 + 20)
= 32 square units
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