. find the sides of the two squares
Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m
Solution: Let the sides of the two squares be x m and y m.
Therefore, their perimeter will be 4x and 4y respectively and their areas will be x2 and y2 respectively.
It is given that 4x − 4y = 24 or x − y = 6
x = y + 6
However, side of a square cannot be negative.
Hence, the sides of the squares are 12 m and (12 + 6) m = 18 m