. For a particle executing SHM the displacement x given by x = A cos
(a) I, III (b) II, IV
(c) II, III (d) I, IV
Best Answer
Potential energy is minimum (in this case zero) at mean position (x = 0) and maximum at extreme positions (x = ¹ A)
At time t = 0, x = A, Hence PE should be maximum. Therefore, graph I is correct. Further in graph III, PE is minimum at x = 0. Hence, this is also correct
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