. Given that the equilibrium constant for the reaction


 2SO2( g) + O2 ( g) ⇌ 2SO3( g), has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? [AIPMT (Mains)-2012]

SO3( g) ⇌ SO2( g) + 1/2O2( g)

a) 1.8×10-3

(b) 3.6×10-3

(c) 6.0×10-2

(d) 1.3×10-5

 

Best Answer

 Correct Option is : (c) 

2SO2+O2 ⟹2SO3 ; Kc=

 

SO2+1/2O2  ;SO3'  Kc'=√x 

Reversing,

SO3⇌SO2+1/2O2 ; Kc''=1/√x

Given : x=278

∴ Kc''=1/√278=6.0×10-2

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