. Given that the equilibrium constant for the reaction
2SO2( g) + O2 ( g) ⇌ 2SO3( g), has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? [AIPMT (Mains)-2012]
SO3( g) ⇌ SO2( g) + 1/2O2( g)
a) 1.8×10-3
(b) 3.6×10-3
(c) 6.0×10-2
(d) 1.3×10-5
Best Answer
Correct Option is : (c)
2SO2+O2 ⟹2SO3 ; Kc=x
SO2+1/2O2 ;SO3' Kc'=√x
Reversing,
SO3⇌SO2+1/2O2 ; Kc''=1/√x
Given : x=278
∴ Kc''=1/√278=6.0×10-2
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