. If NaCl is doped with 10-3 mol percent
of What is the concentration of cation vacancies?SrC12
NaCl is doped with 10-3 mol percent of SrC12
Then we can define that 100 moles of NaCl are doped with 0.001 moles of SrC12
Thus 1 mole of NaCl is doped with 0.001/100=10-5 moles of SrC12
This can also be defined as 10-5 moles of Sr2+ cations.
This defines that one Sr2+ ion creates one cation vacancy.
So 10-5 moles of Sr2+ will create 10-5 moles of cation vacancies which will be calculated by just multiplying it by avogadro number
Final answer: Thus, 6.0221018 cation vacancies per mole of NaCl.