. If NaCl is doped with 10-3 mol percent

Best Answer

Solution:

NaCl is doped with 10^-3  mol percent of  SrC1₂

Then we can define that 100 moles of NaCl are doped with 0.001 moles of SrC1₂

Thus 1 mole of NaCl is doped with 0.001/100=10^-5 moles of SrC1₂

This can also be defined as 10^-5 moles of Sr²⁺ cations.

This defines that one Sr²⁺ ion creates one cation vacancy.

So 10^-5 moles of Sr²⁺ will create 10^-5  moles of cation vacancies which will be calculated by just multiplying it by avogadro number

10^-5×6.022×10²³=6.022×10¹⁸

Final answer: Thus, 6.02210¹⁸ cation vacancies per mole of NaCl.