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- In a single throw of two dice, find the probability that neither a doublet nor a total of 9 will appear
. In a single throw of two dice, find the probability that neither a doublet nor a total of 9 will appear
Best Answer
Sol: Total number of cases = 62 = 36
Favourable outcomes for 9 as sum = (3, 6), (6, 3), (4, 5), (5, 4) = 4
Total = 6 + 4 = 10 cases
P (Neither doublet nor total of 9)= 26/36= 13/18
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