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- In figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E
. In figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E
Prove that AEB = 60°
Best Answer
Sol: Jion OC,OD and BC
In triangle OCD, we have
OC = OD = CD
OCD is a equilateral
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