. In the expansion of
[71/3+111/9] 6561 , the number of terms free from radicals is
A. 730
B. 715
C. 725
D. 750
Best Answer
Ans: A
Sol: 
Total number of terms = 6562 with first and last term free from radical sign.
Hence 729 +1 = 730 terms will be free from radical sign.
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