. In which case is number of molecules of water maximum
(a) 18 mL of water
(b) 0.18 g of water
(c) 0.00224 L of water vapours at 1 atm and 273 K
(d) 10-3 mol of water
Best Answer
Correct Option Is : (a)
Explanation :
1 mole of water= 6.022 × 1023 molecules= 18 gram of water
(a) Mass of water = volume × density=18×1=18 g water = mole NA=18 / 18NA=NA molecules
(b) Molecules of water = mole × NA=0.18 / 18NA = 10-2NA
(c) Moles of water =0.00224 / 22.4=10-4
Molecules of water = mole × NA=10-4NA
(d) Molecules of water = mole × NA=10-3NA
Hence, maximum number of water molecules are present in 18mL of water which is equal to avogadro number of molecules.
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