. In which case is number of molecules of water maximum


(a) 18 mL of water

(b) 0.18 g of water

(c) 0.00224 L of water vapours at 1 atm and 273 K

(d) 10-3 mol of water

Best Answer

Correct Option Is : (a)

Explanation :

 1 mole of water= 6.022 × 1023 molecules= 18 gram of water

(a) Mass of water = volume × density=18×1=18 g water = mole NA=18 / 18NA=NA molecules

(b) Molecules of water = mole × NA=0.18 / 18NA = 10-2N

(c) Moles of water =0.00224 / 22.4=10-4

Molecules of water = mole × NA=10-4NA

(d) Molecules of water = mole × NA=10-3NA

Hence, maximum number of water molecules are present in 18mL of water which is equal to avogadro number of molecules.

 

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