. Joseph jogs from one end A to the other end B of a straight 300 m


road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?

Best Answer

Answer: Given, distance covered from point A to point B = 300 meters

Distance covered from point A to point C = 300m + 100m = 400 meters

Time taken to travel from point A to point B = 2 minutes and 30 seconds = 150 seconds

Time taken to travel from point A to point C = 2 min 30 secs + 1 min = 210 seconds

Displacement from A to B = 300 meters

Displacement from A to C = 300m – 100m = 200 meters

Average speed = total distance travelled/ total time taken

Average velocity = total displacement/ total time taken

Therefore, the average speed while traveling from A to B = 300/150 ms-1 = 2 m/s

Average speed while traveling from A to C = 400/210 ms-1= 1.9 m/s

Average velocity while traveling from A to B =300/150 ms-1= 2 m/s

Average velocity while traveling from A to C =200/210 ms-1= 0.95 m/s

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