. Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm
and ∠ B = 90°. BD is theperpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangentsfrom A to this circle.
Solution:Steps of construction:
i. Draw a line segment AB = 6 cm
ii. Draw a right angle at point B and then, BC = 8 cm.
iii. Now, draw a perpendicular BD to AC.
iv. We know: In a right triangle, hypotenuse is the diameter of circum circle
v. Considering BC as diameter, draw a circle passing through points B, C and D.
vi. Join A to O and taking AO as diameter, draw second circle.
vii. From point A, draw tangents AB and AP.