. Moment of inertia of uniform rod of mass M and length L about an axis through its centre and perpendicular to its length is given by


ML2/12 Now consider one such rod pivoted at its centre, free to rotate in a vertical plane. The rod is at rest in the vertical position. A bullet of mass M moving horizontally at a speed v strikes and embedded in one end of the rod. The angular velocity of the rod just after the collision will be

A. V/L

B. 2v/L

C. 3v/2L

D. 6v/2L

Best Answer

Ans: Initial angular momentum of the system = Angular momentum of bullet before collision = Mv(L/2).........(1)

let the rod rotates with angular velocity w

were

 

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