. Neon gas is generally used in the signboards

Best Answer

Explanation-

a. Wavelength(λ) emitted by neon gas=616nm =616 x 10^-9 m

Frequency(ν)= c /λ

3x10⁸ / 616×10^-9 Where, C= 3x10⁸

=4.87 x 10¹⁴ s^-1

b. Distance travelled= s x t 

3x10⁸ x 30= 9 x 10⁹m

c. Energy=hν

6.626 x 10^-34 x 4.87 x 10¹⁴ = 32.2 x 10^-20 J

d. No. of quanta in 2J of energy= 2/ 32.2 x 10^-20

=6.2 x 10¹⁸ 

Final Answer-

Neon gas is generally used in the signboards. If it emits strongly at 616 nm

Calculate:

(a) The frequency of emission= 4.87 x 1014 s^-1 

(b) Distance travelled by this radiation in 30 s= 9 x 10⁹m

(c) The energy of quantum =32.2 x 10^-20 J

(d) The number of quanta present, if it produces 2 J of energy=6.2 x 10¹⁸