. On mixing 10 mL of acetone with 40 mL
of chloroform, the total volume of the solution is:
A: < 50 mL
B: > 50 mL
C: = 50 mL
D: Can not be predicted
- Chloroform and acetone hydrogen bonding between the two molecules.
- Due to which it shows negative deviations from Raoult’s law.
- Hence, there will be a slight decrease in volume.
Hence the total volume of the solution is < 50 mL i.e option (A).