. Oxidation states of P in H4P2O5
H4P2O6, H4P2O7, are respectively:
A: + 3, + 5, + 4
B: + 5, + 3, + 4
C: + 5, + 4, + 3
D: + 3, + 4, + 5
Best Answer
Explanation-
1. In H4P2O5
The oxidation number of H=+1
Let oxidation number of P=x
The oxidation state of O= -2
4+2x-10=0
-6+2x=0
-6=-2x
x=+3
2. H4P2O6
The oxidation number of H=+1
Let oxidation number of P=x
The oxidation state of O= -2
4+2x-12=0
-8+2x=0
-8=-2x
x=+4
3. H4P2O7
Oxidation number of H=+1
Let oxidation number of P=x
Oxidation state of O= -2
4+2x-14=0
-10+2x=0
-10=-2x
x=+5
Final Answer-
So, The correct option is D.
Oxidation states of P in H4P2O5, H4P2O6, H4P2O4, are respectively: + 3, + 4, + 5
Related questions
