. Oxidation states of P in H4P2O5


H4P2O6, H4P2O7, are respectively:

A: + 3, + 5, + 4

B: + 5, + 3, + 4

C: + 5, + 4, + 3

D: + 3, + 4, + 5

 

Best Answer

Explanation-

1. In H4P2O                                           

The oxidation number of H=+1                                                               

Let oxidation number of P=x

The oxidation state of O= -2

4+2x-10=0

-6+2x=0

-6=-2x

x=+3

2. H4P2O6

The oxidation number of H=+1 

Let oxidation number of P=x

The oxidation state of O= -2

4+2x-12=0

-8+2x=0

-8=-2x

x=+4

3. H4P2O7

Oxidation number of H=+1 

Let oxidation number of P=x

Oxidation state of O= -2

4+2x-14=0

-10+2x=0

-10=-2x

x=+5

Final Answer-

So, The correct option is D. 

Oxidation states of P in H4P2O5,  H4P2O6, H4P2O4, are respectively: + 3, + 4, + 5

 

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