. Percentage of Se in peroxidase anhydrous enzyme


Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4 ) then minimum molecular weight of peroxidase anhydrous enzyme is

(a) 1.568×104

(b) 1.568×103

(c) 15.68

(d) 2.136×104

Best Answer

Correct Option is: (A)

Percentage of Se given= 0.5%

Let molecular mass of enzyme be x g.

In 1 molecule of enzyme, atleast 1 Se atom must be present.

Atomic mass of Se = 78.4g

ATQ, 0.5/100 x = 78.4

Solving the above equation, we get x= 1.568×104.

Therefore, molecular weight of enzyme is 1.568×104.

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