. Percentage of Se in peroxidase anhydrous enzyme
Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4 ) then minimum molecular weight of peroxidase anhydrous enzyme is
(a) 1.568×104
(b) 1.568×103
(c) 15.68
(d) 2.136×104
Best Answer
Correct Option is: (A)
Percentage of Se given= 0.5%
Let molecular mass of enzyme be x g.
In 1 molecule of enzyme, atleast 1 Se atom must be present.
Atomic mass of Se = 78.4g
ATQ, 0.5/100 x = 78.4
Solving the above equation, we get x= 1.568×104.
Therefore, molecular weight of enzyme is 1.568×104.
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