. PQR is a triangle right angled at P
and M is a point on QR such that PM ⊥ QR. Show that PM2=QM.MR
When a perpendicular is drawn from the vertex of a right triangle's right angle to the hypotenuse, we know that triangles
on both sides of the perpendicular are similar to each other and to the complete triangle.
As per the question, PQR is a triangle right angled at P and M is a point on QR such that PM is perpendicular to QR.
A figure is drawn.
Hence, it is proved that PM2=QM.MR.