. Rate law for the reaction
A + 2B→ C is found to be, Rate = k[A][B] The concentration of reactant 'B' is doubled, keeping the concentration of 'A' constant, the value of the rate constant will be:
A: the same
B: doubled
C: quadrupled
D: halved
Best Answer
Explanation:
For the rate law Rate = k[A][B]
Where K is rate constant
If the concentration of reactant 'B' is doubled, keeping the concentration of 'A' constant, the value of rate constant will remain the same.
As the rate constant does not depend on concentration.
It depends only on the temperature.
Final Answer:
Hence the correct answer is (A) rate constant will remain the same.
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