. Solve(1+cotA-cosecA)(1+tanA+secA)=2
Best Answer
Explanation:
LHS = (1 + cot A - cosec A)(1+ tan A + sec A)
= (1 + Cos ASin A - 1Sin A) (1+ Sin ACos A - 1Cos A)
= (Sin A + Cos A -1Sin A) (Sin A + Cos A + 1Cos A)
= (Sin A + Cos A -1) (Sin A + Cos A + 1)Sin A Cos A
= (Sin A + Cos A)2 - (1)2 Sin A Cos A
= (Sin 2A + Cos 2A + 2 Sin A Cos A - 1 Sin A Cos A
= ( 1 + 2 Sin A Cos A - 1 )Sin A Cos
= 2 Sin A Cos A Sin A Cos A=2
Final Answer:
Hence, we get 2, as the answer.
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