. Speeds of two identical cars are u and 4u at a sufficient instant
What is the ratio of the respective distance at which the two cars are stopped from that instant?
Best Answer
Answer:
Explanation:
The velocity of the first car can be written as
u12=2as1
s1=u2/2a
And for second car
u22=2as2
s2=(4u)2/2a
The two car stopped
s1:s2=1:16
Final Answer:
The two cars stopped at the instant when the displacement ratio will be 1:16.
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