. The amount of sugar


sugar (C12H22O11) required to prepare 2L of its 0.1 M aqueous solution is:

A: 68.4g

B: 17.1g

C: 34.2g

D: 136.8g

 

Best Answer

Explanation:

  • The formula of Mola Molarity = No. of moles of solute / Vol. of solution(in L)

No. of moles of C12H22O11 = Given weight / Molecular weight

Molecular weight of C12H22O11 = 12  12 + 22 1 +16 11

= 144 + 22 + 176

= 342

No. of moles of C12H22O11 = Given weight / Molecular weight

= w / 342

Molarity = No. of moles of soluteVol. of solution(in L)

0.1M = w / 342 × 2 L

= 68.4 g

Final Answer:

Hence, Option (A) is correct.

 

 

Talk to Our counsellor